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What is the point slope equation line with slope -13 that goes through the point (57)?
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
What is the slope of a line that passes through the point (-5 3) and is parallel to a line that passes through (213) and (-4-11)?
If you mean: (2, 13) and (-4, -11) then the slope is 4 and both equations will have the same slope of 4 but with different y intercepts
Enter an equation of the form y mx for the line that passes through the origin and has slope 13.?
y=13x
Find th slope if it exists of the line containing the pair of points -5-13 and -17-19?
First we note that the slope does exist between the two points because the two points do not have the same x co-ordinate. Next, we apply the slope formula. slope=(y2-y1)/(x2-x1) Note that it does not matter which point you call as 1 or 2, you will still get the same result. For this example we will call point (-5,-13) as point 1 and (-17,-19) as point 2. Therefore: slope=(-19-(-13)) / (-17-(-5)) = (-6) / (-12) = 1/2 Therefore, the slope of the line containing the points (-5,-13) and (-17,-19) is 1/2.
What is the perpendicular equation that meets the line of 7 3 and -6 1 at its midpoint showing work?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5
