Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
Flat slope is slope equals zero.
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
Slope = 4
2x-5y+15=0 -5y=-2x-15 y=(2/5)x+3
The slope of the line that represents the graph of that equation is 15.
4
36x-9y=15 36x-15=9y y=4x-15/4 remember slope is the m on y=mx+b so slope=4
36x-9y = 15 -9y = -36x+15 y = 4x-5/3 in slope intercept form
-3/5
y = -1.2x-3 in slope intercept form
Slope = -6/5 = -1.2 y-intercept = -3
15
Get in slope intercept form. 3X + 5Y = 15 5Y = -3X + 15 Y = -3/5X + 3 -3/5 is the slope of this line and the line parallel to this line
The slope is 1/3 and the y-intercept is -1.
Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3
The slope of a straight line perpendicular to another is the negative reciprocal So you have 3x+y = 15 y = -3x+15 here the slope is -3 ( the number in front of the x is slope, m, remember?) so the slope of the line perpendicular is minus (1/-3) = 1/3