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If you mean: y = 6x+2 then its perpendicular line is -1/6

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Q: What is the slope of a line perpendicular to the line with equation y 6x 2?
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What is the slope of a line perpendicular to the line with equation y6x plus 2?

If you mean: y = 6x+2 then its perpendicular line is -1/6.


What is the slope of a line that is perpendicular to 6x 3y-9?

If you mean: 6x+3y = -9 then the perpendicular slope works out as 1/2 or 0.5


What is the slope of line that would be perpendicular to 6x-2y equals 12?

Slope of given line = 3 So slope of perpendicular = -1/3


What is the slope of a line that is perpendicular to 6x plus 3y equals -9?

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What equation that represents the line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

Let 'y' be the first equation and 'z' be the perpendicular one. 2y = -6x + 8 y = -3x + 4 A slope is perpendicular to another slope if and only if its slope is a negative reciporical of that slope. So z = x/3 + b and we know that b = 5, so z = x/3 + 5


What is in its general form the perpendicular bisector equation cutting through the line segment of -7 -3 and -1 -4?

Points: (-7, -3) and (-1, -4) Slope: -1/6 Perpendicular slope: 6 Mid-point (-4, -3.5) Equation: y - -3.5 = 6(x - -4) => y = 6x+20.5 Perpendicular bisector equation in its general form: 6x -y+20.5 = 0


What line perpendicular to 2y equals -6x plus 8 if the y-intercept is 5?

Given a line with slope m, the slope of a perpendicular line is -1/m. So put the equation in slope-intercept form:y = -3x + 4.So slope = -3, and slope of perpendicular line = 1/3. So the new line is: y = mx + b, m = 1/3 and b = 5.y = x/3 + 5


Find the slope of the line determined by the following equation 6x-y equals 42?

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What is the slope of the line y equals 6x?

The equation of a line is of the form y = mx + b. m is the slope and b is the y-intercept. Therefore, the slope of the line y = 6x is 6.


What is the perpendicular bisector equation of the line segment with endpoints of -7 -3 and -1 -4?

End points: (-7, -3) and (-1, -4) Midpoint: (-4, -3.5) Slope: -1/6 Perpendicular slope: 6 Perpendicular bisector equation: y--3.5 = 6(x--4) => y = 6x+20.5


What is the slope of the line given by the equation below y equals 6x - 2?

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What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?

Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5