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Write the given equation in the slope-intercept form, y = mx + b, where m is the slope of the line.

9x - 3y = -81 (subtract 9x to both sides)

-3y = -9x - 81 (divide by -3 to both sides)

y = 3x + 27

Thus, the slope of the line is 3.

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Q: What is the slope of the line 9x-3y equals -81?

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x: x2 - 81 = 0

27 x 3 = 81

x2 = 81 Square root both sides:- x = +/- 9

The number is three.

It is: (81*9*64)+19 = 46,675

Related questions

I'm assuming here that this line is a straight line. If so, it has the general equation y=mx+c (where m= the gradient/slope and c is the intercept). Substituting in the values provided in the question, we yield; 15= (9x9)+c We then solve and rearrange; 15=81+c 15-81=c -66=c. Therefore, the slope intercept is -66

Points: (2, -2) and (8, 1)Slope: 1/2

If you mean points of (055, 18) and (566, 81) then the slope works out as 9/73

It is 13x + y = 81.

81% = 81/100

82-1=81

81 x 81 = 6561

How about: 9 times 9 = 81 or 81 times 1 = 81

54

81 * 22 = 1,782

100x2-81

3 to the power of 4 = 81