If you mean: (4, 3) and (3, 8) then the slope works out as -5
To find the slope of the line passing through two points (x1, y1) and (x2, y2), you use the formula: slope = (y2 - y1) / (x2 - x1). In this case, the points are (5, 8) and (-3, 7). Plugging the values into the formula, we get slope = (7 - 8) / (-3 - 5) = -1 / -8 = 1/8. Therefore, the slope of the line passing through the points (5, 8) and (-3, 7) is 1/8.
Find the slope of these points. (4,1) and (5,-1) m(slope) = Y2 - Y1/X2 - X1 m = -1 - 1/5 - 4 = -2/1 or - 2 Now I prefer to use one set of nice points and this formula, the point slope formula. Use (4,1) Y - Y1 = m(X - X1) Y - 1 = - 2(X - 4) distribute the slope Y - 1 = - 2X + 8 add 1 to each side Y = - 2X + 9 -----------------the equation
Points: (2, 5) and (8, 7) slope = 1/3Points: (-3, 1) and (-2, -2) slope = -3The lines are perpendicular to each other
We want a line that passes through the points (22,0) and (-2,3)The general formula for a line is y = mx +bWhere M is our slope, and B is the y-intercept.We don't know either, so we have to use the points given to figure out 1) the slope 2) the y intercept.You can find slope by using the slope formuladifference in y's divided by the difference in x's(22,0) is (x,y) and (-2,3) is also (x,y)(0 - 3)/(22 - (-2))-3/24 = -1/8Our slope is -1/8.Now we plug m = -1/8 into the general formula y = mx +b.We also pick ONE set of points, and plug that in for x and y. (it's easier to pick smaller numbers)y = mx + b3 = (-1/8)(-2) + bNow we solve for b.3 = 1/4 + b3 - 1/4 = b12/4 - 1/4 = b (I changed 3 to a fraction to work with -1/4)11/4 = b(or 2 and 3/4)Now we know both the slope, m = -1/8 and the y-intercept, b = 11/4.We just put these into the general form of a line and we have our equation.y = mx + by = -1/8x +11/4
You need two numbers to specify each point.To actually calculate the slope, divide (difference in y-coordinates) by (difference in x-coordinates).If you mean: (-1, 2) and (4, 3) then it is 1/5
To find the slope of the line passing through two points (x1, y1) and (x2, y2), you use the formula: slope = (y2 - y1) / (x2 - x1). In this case, the points are (5, 8) and (-3, 7). Plugging the values into the formula, we get slope = (7 - 8) / (-3 - 5) = -1 / -8 = 1/8. Therefore, the slope of the line passing through the points (5, 8) and (-3, 7) is 1/8.
Two sets of points are needed to determine the slope of a line
Let's see this by an example. Find the slope m of the line that passes through the points (-3, 2) and (-2, 4). Definition of slope: The slope of the line that passes through distinct points (x1, y1) and (x2, y2) is Change in y/Change in x = Rise/ Run = (y2 - y1)/(x2 - x1) where x2 - x1 is different than 0. Solution: Let (x1, y1) = (-3, 2) and (x2, y2) = ( -2, 4). The slope is: m = (y2 - y1)/(x2 - x1) = (4 - 2)/[-2 - (-3)] = 2/1 = 2 The slope of the line is 2, indicating that there is a vertical change, a rise, of 2 units for each horizontal change, a run, of 1 unit. The slope is positive, and the line rises from left to right.
Find the slope of these points. (4,1) and (5,-1) m(slope) = Y2 - Y1/X2 - X1 m = -1 - 1/5 - 4 = -2/1 or - 2 Now I prefer to use one set of nice points and this formula, the point slope formula. Use (4,1) Y - Y1 = m(X - X1) Y - 1 = - 2(X - 4) distribute the slope Y - 1 = - 2X + 8 add 1 to each side Y = - 2X + 9 -----------------the equation
Yes, a plane can be uniquely defined by three points as long as the three points are not colinear. (Three points are colinear if there is a straight line that passes through all three points.)
It has 8. Each passes through the centre. Four pass through vertices, four pass through the mid-points of opposite sides
It has 8. Each passes through the centre. Four pass through vertices, four pass through the mid-points of opposite sides
Points: (4, -6) and (2, -3) so slope is -3/2 Points: (6, 5) and (3, 3) so slope is 2/3 The lines are perpendicular to each other
It has 8. Each passes through the centre. Four pass through vertices, four pass through the mid-points of opposite sides.
Points: (2, 5) and (8, 7) slope = 1/3Points: (-3, 1) and (-2, -2) slope = -3The lines are perpendicular to each other
There is not enough information to answer this question. As currently written, a geometric point with only one variable is operating only on the x-axis (one dimensional). Asking the slope between two points that only exist on the x-axis is automatically zero. Slope is normally calculated using points on a two-dimesional grid with each point being represented by (x,y). To calculate the slope in this case you take the change in y divided by the change in x. Example: Find the slope of the line through the points (-13,4) and (17,14). Slope = Change in Y/Change in X = (-13-17)/(4-14) = -30/-10 = 3
Parallel. So you have two couples of points and each of them determine a line. L1 passes through (1,2) and (9, 9). m1 = (9-2)/(9-1) =7/8 L2 passes through (12.11) and (4,4). m2 = (11-4)/(12-4) = 7/8 Since both lines have the same slope, they are parallel.