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We want a line that passes through the points (22,0) and (-2,3)

The general formula for a line is y = mx +b

Where M is our slope, and B is the y-intercept.

We don't know either, so we have to use the points given to figure out 1) the slope 2) the y intercept.

You can find slope by using the slope formula

difference in y's divided by the difference in x's

(22,0) is (x,y) and (-2,3) is also (x,y)

(0 - 3)/(22 - (-2))

-3/24 = -1/8

Our slope is -1/8.

Now we plug m = -1/8 into the general formula y = mx +b.

We also pick ONE set of points, and plug that in for x and y. (it's easier to pick smaller numbers)

y = mx + b

3 = (-1/8)(-2) + b

Now we solve for b.

3 = 1/4 + b

3 - 1/4 = b

12/4 - 1/4 = b (I changed 3 to a fraction to work with -1/4)

11/4 = b

(or 2 and 3/4)

Now we know both the slope, m = -1/8 and the y-intercept, b = 11/4.

We just put these into the general form of a line and we have our equation.

y = mx + b

y = -1/8x +11/4

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Q: Write in slope-intercept form the equation of the line through each pair of points 22 0 0 and -2 3?
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