We want a line that passes through the points (22,0) and (-2,3)
The general formula for a line is y = mx +b
Where M is our slope, and B is the y-intercept.
We don't know either, so we have to use the points given to figure out 1) the slope 2) the y intercept.
You can find slope by using the slope formula
difference in y's divided by the difference in x's
(22,0) is (x,y) and (-2,3) is also (x,y)
(0 - 3)/(22 - (-2))
-3/24 = -1/8
Our slope is -1/8.
Now we plug m = -1/8 into the general formula y = mx +b.
We also pick ONE set of points, and plug that in for x and y. (it's easier to pick smaller numbers)
y = mx + b
3 = (-1/8)(-2) + b
Now we solve for b.
3 = 1/4 + b
3 - 1/4 = b
12/4 - 1/4 = b (I changed 3 to a fraction to work with -1/4)
11/4 = b
(or 2 and 3/4)
Now we know both the slope, m = -1/8 and the y-intercept, b = 11/4.
We just put these into the general form of a line and we have our equation.
y = mx + b
y = -1/8x +11/4
Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9
If you mean points of (3, 4) and (5, 8) then the slope is 2 and the equation is y=2x-2
I need step by step on my graphic calculator on how to write an equation
write a rule as an equation
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
y = 2x + 1.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
The formula for a line is: Y = mX + b
Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
Slope-intercept form
Y=4x+3
Points: (5, -2) and (4, 3)Slope: -5Equation: y = -5x+23
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
the Equation of a Line Given That You Know Two Points it Passes Through.
y=-3x-2
This starts with the collocation circle to go through the three points on the curve. First write the equation of a circle. Then write three equations that force the collocation circle to go through the three points on the curve. Last, solve the equations for a, b, and r.