0
What else can I help you with?
What is the standard form of the equation of the line with a slope of two-thirds passing through the points negative 5 and nine?
With a slope of 2/3, the slope-intercept form of the equation is: y = (2/3)x + b where b is the y-intercept. If it passes through the point (-5, 9) -- I assume that's what you meant in the question -- then you substitute x=-5 and y=9: 9 = (2/3)(-5) + b and solve for b: 9 = -10/3 + b b = 9 + 10/3 = 27/3 + 10/3 = 37/3 So now you have y = (2/3)x + 37/3 Multiply both sides by 3: 3y = 2x + 37 Rearrange: 2x - 3y + 37 = 0 which is standard form ax + by + c = 0
What are the factors and prime factors of 37?
1 and 37, 37 is prime.
What is the ratio of 37 divided by 5 to the product 6 multiply 37 divided by 6?
37/5 : 6*37/6 = 37/5 : 37 = 1/5 : 1 = 1 : 5
What equals 37 in multiplication?
37 is a prime number, so the only factors that multiply to get it are 1 and 37.
What is the lcm of 17,27, and 37?
The three numbers are coprime so their LCM = 17*27*37 = 16983
What is the slope of the line that passes through the points (13) and (37)?
If you mean points of (1, 3) and (3, 7) then the slope works out as 2
What is the slope of of the line that contains the points (6-2) and (-37)?
Points: (2, 6) and (-1, -6)Slope: 4
What is the slope of a line that contains the points (6-2) and (-37)?
If you mean points of (6, -2) and (-3, 7) then the slope works out as -1
What is the equation of this line (01)(25)(37)?
If you mean points of (0, 1) (2, 5) (3, 7) Then the slope is 2 The equation works out as: y = 2x+1
The slope of the best fit line is -2.5 Find the y-intercept of this line 212 37 54?
16
What is the slope if the points are -2-3 and 37?
To find the slope between the points (-2, -3) and (3, 7), use the slope formula: ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Plugging in the values: ( m = \frac{7 - (-3)}{3 - (-2)} = \frac{7 + 3}{3 + 2} = \frac{10}{5} = 2 ). Therefore, the slope is 2.
What is the standard form of the equation of the line with a slope of two-thirds passing through the points negative 5 and nine?
With a slope of 2/3, the slope-intercept form of the equation is: y = (2/3)x + b where b is the y-intercept. If it passes through the point (-5, 9) -- I assume that's what you meant in the question -- then you substitute x=-5 and y=9: 9 = (2/3)(-5) + b and solve for b: 9 = -10/3 + b b = 9 + 10/3 = 27/3 + 10/3 = 37/3 So now you have y = (2/3)x + 37/3 Multiply both sides by 3: 3y = 2x + 37 Rearrange: 2x - 3y + 37 = 0 which is standard form ax + by + c = 0
What is Mike Bibby Career High Points?
37 points
Write an equation for the line that passes through (3 8) and is parallel to y equals 1 fifth left parenthesis x plus 4 right parenthesis. Show your work.?
If the slope of the given equation is 1/5 then the slope of the parallel equation will be the same which works out as: y-8 = 1/5(x-3) => y = 1/5x+7.4
How many points did the biggest buck have?
37
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point (37)?
To write the equation in slope-intercept form (y = mx + b), we start with the slope (m) of 2 and the point (3, 7). We can use the point to find the y-intercept (b). Substituting the point into the equation gives us 7 = 2(3) + b, which simplifies to 7 = 6 + b. Thus, b = 1, and the equation in slope-intercept form is y = 2x + 1.
How do you write the standard form of the equation for the line that passes through the points -8 and-7 and -5 and -5?
(- 8, - 7) and (- 5, - 5)Need slope first. m = Y2 - Y1/X2 - X1m = - 5 - ( - 7)/- 5 - (- 8)m = 2/3========Now, I use point slope form to get us half way thereY - Y1 =m(X - X1) ( - 8, - 7) points usedY - (- 7) = 2/3[X - (- 8)Y + 7 = 2/3(X + 8)Y + 7 = (2/3)X + 16/37 = 21/3, soY + 21/3 = (2/3)X + 16/3Y = (2/3)X - 5/3===========================standard form
