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How do you write the standard form of the equation for the line that passes through the points -8 and-7 and -5 and -5?
(- 8, - 7) and (- 5, - 5)
Need slope first. m = Y2 - Y1/X2 - X1
m = - 5 - ( - 7)/- 5 - (- 8)
m = 2/3
========Now, I use point slope form to get us half way there
Y - Y1 =m(X - X1) ( - 8, - 7) points used
Y - (- 7) = 2/3[X - (- 8)
Y + 7 = 2/3(X + 8)
Y + 7 = (2/3)X + 16/3
7 = 21/3, so
Y + 21/3 = (2/3)X + 16/3
Y = (2/3)X - 5/3
===========================standard form
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