It rotated the line about the point of intersection with the y-axis.
For example, if the slope at a certain point is 1.5, you can draw a line that goes through the specified point, with that slope. The line would represent the slope at that point. If you want to graph the slope at ALL POINTS, take the derivative of the function, and graph the derivative. The derivative shows the slope of a function at all points.
When something has a constant rate of change it means that it has a linear graph. The function can be written in the slope intercept form of y = mx + b.
slope
In the graph, the slope means that, what is the corresponding value of f while x vary, for example, f(x)=2x+3, when x=1, then f=5 etc
The graph of a linear function is a line with a constant slope. The graph of an exponential function is a curve with a non-constant slope. The slope of a given curve at a specified point is the derivative evaluated at that point.
The linear parent function is y=x. The line on a graph passes through the origin(0,0) with a slope of 1. The line will face left to right on the graph like this /.
Yes, with no slope. It will show up as a horizontal line if you graph it.
linear?
You can graph a linear equation slope intercept by solving the equation and plugging in the numbers : y=mx+b
No. A linear graph has the same slope anywhere.
acceleration
You could put the equation in slope-intercept form or in parent linear function or even make a table of values.
plotting a slope means plotting a graph of y against x.to get the linear function ,the only thing to do is to know whether the value of y and the equivalent value of x at the point if its a well plotted slope normally any choosen point will be the same .assuming it is not a curve.if not replot.
It rotated the line about the point of intersection with the y-axis.
The slope of a speed-time linear graph represents acceleration. If the line is flat (zero slope), the object is moving at a constant speed. A positive slope indicates acceleration, while a negative slope represents deceleration.
If it was linear to start with it will still be linear. The slope will change to its reciprocal. The y-intercept will be unchanged (but it will look different)