To calculate the slope, simply calculate (difference in y-coordinates) divided by (difference in x-coordinates).
Points: (-1, -1) and (-3, 2) Slope: -3/2
Don't write "the following" if you don't provide a list.
Points: (0, -1) and (-2, -4)Slope: 3/2
No. If you have more than two points for a linear function any two points can be used to find the slope.
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
It has no slope.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
32
If you mean points of (3, 1) and (0, -5) then the slope is 2
If you mean points of (-4, 3) and (3, 1) then the slope is -2/7
If you mean points: (-3, -5) and (3, 2) then the slope works out as 7/6
84
Don't write "the following" if you don't provide a list.
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.
Points: (8, 2) and (0, 0) Slope: 1/4 or 0.25 Equation: y = 0.25x
This will equal -i. If you think about complex numbers graphically, it helps:i0 = +1, which points to the righti1 = +i, which points up.i2 = -1, which points to the left.i3 = -i, which points down.i4 = +1, and it repeats in fours.So 32 is a multiple of 4, i32 will be the same as i4. So 31 is one less than 32, and i31 will be the same as i3, which is -i.