Points: (-3, -1) and (3, -2)
Slope: -1/6
Points: (-1, -1) and (-3, 2) Slope: -3/2
Don't write "the following" if you don't provide a list.
Points: (0, -1) and (-2, -4)Slope: 3/2
No. If you have more than two points for a linear function any two points can be used to find the slope.
If: 11x-8y = 32 Then: -8y = -11x+32 And: y = 1.375x-4 in slope-intercept form
It has no slope.
Points: (-1, -1) and (-3, 2) Slope: -3/2
Points: (-1, -1) and (-3, 2) Slope: -3/2
32
If you mean points of (-4, 3) and (3, 1) then the slope is -2/7
If you mean points of (3, 1) and (0, -5) then the slope is 2
If you mean points: (-3, -5) and (3, 2) then the slope works out as 7/6
84
Don't write "the following" if you don't provide a list.
The slope of a line that has the points 3, (-4), and has a slope of 2 is 2.
Points: (8, 2) and (0, 0) Slope: 1/4 or 0.25 Equation: y = 0.25x
Points: (12, 8) and (17, 16) Slope: 8/5 Equation: 5y = 8x-32