{-1,-2}
2x + x + 4 +2x = x + 20 5x + 4 = x + 20 5x - x = 20 - 4 4x = 16 x = 4
1
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
6x + 12x + 2x = 80 20x = 80 x = 4
x = 0
The answer is (3.5)2 plus (4)2 equals 410.
x = 0 and y = 4
1 solution
5 - 2x = 8 x = -1 and 1/2 4x = 6 x = 6/4 or 3/2
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
2x + 4 = 14 (subtract 4 from both sides) 2x = 10 (divide both sides by 2) x = 5
2x + 4 = 8Subtract 4 from each side of the equation:2x = 4Divide each side by 2:x = 2
If 4x - 2x + 4 = 10, the solution is 2x + 4 = 10 and x = 3.
x equals 4
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
If x=4 then 2x+7 =