x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
6
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
(x-9)(x-5)=0x²-14x+45=0
Using the quadratic equation formula: x = -5-/+ the square root of 7
1
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5
The roots are: x = -5 and x = -9
-5
6
It is a linear equation in x. The equation has the solution x = 0.
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
Notice that the left side of the equation is a perfect square (x - 7)2 = x2 -14x + 49. so (x - 7)2 = 4. Take square root of both sides: x - 7 = ± 2, x = 9, or x = 5.
The solution to the equation is x = 26/5 = 5.2
Yes