14x = 5 x = 5/14
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
Using the quadratic equation formula: x = -5-/+ the square root of 7
(2, 3) is a solution only if it satisfies the equation. x + 5y = 4 (2) + 5(3) =? 4 2 + 15 =? 4 17 = 4 False Therefore, (2, 3) is not a solution to the given equation.
Not until it equals something. Equations have equals signs.
-5
It is a linear equation in x. The equation has the solution x = 0.
14x = 5 x = 5/14
It is also x = 5 8zx + 5 = 2j + 3 → 8zx + 2 = 2j → 4zx + 1 = j Which is the first equation, which has a solution x = 5.
There is one solution. To find it, divide both sides of the equation by 2. This leaves you with x=5, where 5 is your solution.
4y + 2 = 5y - 5
The solution to the equation is x = 26/5 = 5.2
Yes
x = 19
The 'solution' of an equation is the number which, when substitutedfor the variable, makes the equation a true statement.You have said: [ x = 5 ] .We claim that the solution is '5', because when '5' is substituted for 'x',the equation reads5 = 5and that's a true statement.
X=2
The equation does not have a solution.