The solution set is x = 5n + 3 where n is any integer.
x/3 + 7 = 5 x/3 = -2 x = -6
(2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 will have a remainder of 1 when divided by 2, 3, 4, 5, 6, 7, 8, or 9. (2 x 3 x 4 x 5 x 6 x 7 x 8 x 9) + 1 = 362,881
It's the same as 1 divided by (3 to the power 5).
x + 5 > 10 and x -2 < 1 This results in x > 5 and x < 3 There is no number that is both greater than 5 and less than 3, therefore there is no solution. The thing above is wrong that would make it an "or" statement.
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.
If you mean x/3 = 5 then the value of x is 15
X/5
no. -x over 3-5 is -x Iver -2, which is x divided by 2
If you were to put that in an algebraic expression, it would look like this:3 x 3 + 2 x 5 - 5 x 2 / 10 + 5 / 5 = Solution (Given that there are no parentheses)3 x 3 = 9+ 2=11X 5= 55- 5= 50X 2= 100/ 10= 10+ 5= 15/ 5= 3Therefore the answer is 3
When dividing fractions, multiply by the inverse of the fraction.That is, a/b divided by x/y = a/b times y/x = ay/bxFor example,2/5 divided by 3 = 2/5 x 1/3 = 2/152/5 divided by 1/3 = 2/5 x 3/1 = 6/55 divided by 3 = 5/1 x 1/3 = 5/35 divided by 1/3 = 5/1 x 3/1 = 15/1 (= 15)
8
5/(3/5) = 5 x 5/3 = 5/1 x 5/3 = (5 x 5) / (1 x 3) = 25/3
Where is the answer to the question? 6
(X + 1)/10 = -3/5 take the extreme mean; cross multiply -30 = 5(X + 1) distribute on right -30 = 5X + 5 subtract 5 from each side -35 = 5X divide each side by 5 -7 = X check (-7 + 1)/10 = -3/5 -6/10 = -3/5 same thing, checks
9/1 divided by 3/5 = 9/1 X 5/3 = 3/1 X 5/1 = 15/1 = 15!
3/3-x