Q: What is the square root of 28 minus the squared root of 7?

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3x squared minus 25x minus 28

The square root of 28 or in this case the radical form of 28 will be 2 times radical 7. Since 28 is 4 times 7 and the square root of 4 is two.

The perimeter is 28.

The root is equal to 2*sqrt(7), or 5.291502622......

5.2915 is. (rounded)

Related questions

3x squared minus 25x minus 28

There's nothing to solve. If it equaled something, you could solve it. For example, if x^2 - 28 = 0, then x = the square root of 28, which simplifies to plus or minus 2 times the square root of 7.

Every number is a squared number- it is a square of something. However, 794 is not a perfect square number. 28 squared is 784 and 29 squared is 841. The square root of 794 is 28.1780056072107.

Take the square root of each side of the equation.x = Â± i sqrt(28)

28 is not a perfect square. A perfect square is an integer that is the square of another integer. 9 is a perfect square; it equal to 3 squared, or 3 X 3. Often, such numbers are called simply square numbers. While 28 is not a perfect square, it is a square number in the sense that it has a square root. by definition, the square root of 28 times itself equals 28.

28 does not have a square root.

technically the square root of 28 is to hard to find because it would go on and on, so most math maticians say that the answer to the square root of 28 is the square root of 28.

(x+4)(x-7)

no, 28 has no whole square root; the square root of 49 is 7

First you must square the 6 which the answer is 36. Then you subtract 36 from 8 and the answer is negative 28. Finally you solve negative 28 minus 28 (-28-28) which equals negative 56 (-56).

irrational

28 square root of 6 is approximately 68.59. Plug 28 back to the root will be V4704.