There's nothing to solve. If it equaled something, you could solve it. For example, if x^2 - 28 = 0, then x = the square root of 28, which simplifies to plus or minus 2 times the square root of 7.
Solve this problem -x squared -40x- 80 =0
28^2 (28 x 28) is equal to 784.
If X squared is less than 16, then the absolute value of X is less than the square root of 16. X will be greater than -4 and less than +4.
You fill in for x and solve the equation3(5)^2 - 2(5)15^2 - 10; now solve
If that's x2 times 20 = 0, then x = 0, because only 0 x 20 = 0
Take the square root of each side of the equation.x = ± i sqrt(28)
x=9 squared
If you mean: x squared -14x +45 then when factored it is (x-9)(x-5)
5.
Solve this problem -x squared -40x- 80 =0
Add the x's squared together to get 2x^2+x. You cannot add anymore so the answer is 2x^2+x
If x squared -10 = 0 then x = the square root of 10
whp do you do a 7 suared
28^2 (28 x 28) is equal to 784.
(x-3)(x+2)the answer is x=3
x^(2) - 10x + 16 = 0 Factors of '16', which are, 1,2,4,8,16. Select two numbers from this list that add/subtract to '10' . They are '2' and '8'. Setting up brackets ( x 2)(x 8) Since '16' is positive(+), then both signs must be the same. Since '10x' is negative (-) , then both signs are negative. Hence (x - 2)(x - 8 ) = 0 When x - 2 = 0 x = 2 & when x - 8 = 0 x = 8 So the two answers are ,2, & ,8, .
(x-5)(x+3)