The area of any rectangle is simply its length multiplied by its width so in this case the answer would be 6in x 4in which equals 24in2.
Not always because a 2 by 12 rectangle will have the same area as a 4 by 6 rectangle but they both will have different perimeters.
𝘗𝘦𝘳𝘪𝘮𝘦𝘵𝘦𝘳 = adding up all the sides. So a rectangle has 4 sides. Add up how long each of those 4 sides are and you'll have your answer.Area = length times width.
The rectangle is 6-ft long and 4-ft wide.
The area of a 16 by 6 rectangle is 16*6 = 96 square units.
The area of any rectangle is simply its length multiplied by its width so in this case the answer would be 6in x 4in which equals 24in2.
The area of rectangle is : 24.0
perimeter is the space around an object, area is the space inside of an object.A 4x6 rectangle has a perimeter of 4 + 6 + 4 + 6,A 4x6 rectangle has an area of 4 x 6.
4*6 = 24 square units
The area of a rectangle is found by multiplying its length by its width. 6 ft x 4 ft = 24 sq ft.
Base of rectangle: 24/6 = 4 cm
It is: 6*4 = 24 square units
Not always because a 2 by 12 rectangle will have the same area as a 4 by 6 rectangle but they both will have different perimeters.
It would be a rectangle. The lengths of the sides must be such that the length times the width equals 36: So it could be a square with sides 6; or A rectangle with sides 4 and 9; or A rectangle with sides 3 and 13; or A rectangle with sides 2 and 18; or A rectangle with sides 1 and 36; or A rectangle with sides ½ and 72, etc The rectangle can get as thin as you like and would become longer to accommodate the area.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
The area of the rectangle works out as 7 times 6 = 42 square units
𝘗𝘦𝘳𝘪𝘮𝘦𝘵𝘦𝘳 = adding up all the sides. So a rectangle has 4 sides. Add up how long each of those 4 sides are and you'll have your answer.Area = length times width.