answersLogoWhite

0

σ=2.49

User Avatar

Wiki User

11y ago

What else can I help you with?

Related Questions

What is the standard deviation of 5 5 5 7 9 9 9?

7


What is the standard deviation of 9?

You need more than one number to calculate a standard deviation, so 9 does not have a standard deviation.


What is the variance and standard deviation of 4 7 2 7 9 10 15?

Variance = 17.9047619 Standard Deviation = 4.23140188


What is the mean variance and standard deviation for the numbers 2 4 8 2 9 1 7 11 4 7 1 10 1 5?

5.142857143 is the mean.12.43956044 is the variance.3.526976104 is the standard deviation.


Compute the variance and standard deviation of the following sample data:5 9 10 2 7 9 14?

mean =(5+9+10+2+7+9+14)/7=8 s^2 = Variance = (1/7){(5-8)^2+(9-8)^2+(10-8)^2+(2-6)^2+(7-8)^2+(9-8)^2+(14-8)^2}=14.6666 Standard deviation =s= sqrt(14.6666)=3.8297


Find the range and standard deviation of the data set. 22 18 19 25 27 21 24?

The range is 9 and 3.01 is the standard deviation.


What is a population standard deviation of 2 6 15 9 11 22 1 4 8 19?

7.087547766 is the standard deviation for those figures.


What is the standard deviation of the data set 5 7 9 11 13?

It is approx 2.828


The weights of nine men have a mean of 175 and a standard deviation of 15 what is the standard error of the mean?

(15/sqroot(9))=5 So it is 5


What is the range and standard deviation of 9 15 15 15 16?

9 15 15 15 16 (five data) Range = 16 - 9 = 7 Mean = (9 + 15 + 15 + 15 + 16)/5 = 70/5 = 14 So we have: (9 - 14)2 = (-5)2 = 25 (the square of the difference of data value and the mean value) (15 - 14)2 = 12 = 1, 3(1) = 3 (16 - 14)2 = 22 = 4, the sum is 32 The standard deviation = √(32/5) ≈ 2.5


What is the mean absolute deviation of 2 3 5 4 9 4 3?

Absolute deviation from what?


How do you create data set with larger standard deviation?

Standard deviation is the square root of the sum of the squares of the deviations of each item from the mean, i.e. the square root of the variance. In order to increase the standard deviation, therefore, you need to increase the average deviation from the mean. There are many ways to do this. One is to move each item further away from the mean. For example, take the set [2, 4, 4, 4, 5, 5, 7, 9]. It has a mean of 5 and a standard deviation of 2.14. Multiply each item by 2.2 and subtract 5, giving the set [-1.3, 2.9, 2.9, 2.9, 5, 5, 9.2, 13.4], effectively moving each item 10% further away from the mean. This still has a mean of 5, but the standard deviation is 4.49.