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9 15 15 15 16 (five data)
Range = 16 - 9 = 7
Mean = (9 + 15 + 15 + 15 + 16)/5 = 70/5 = 14
So we have:
(9 - 14)2 = (-5)2 = 25 (the square of the difference of data value and the mean value)
(15 - 14)2 = 12 = 1, 3(1) = 3
(16 - 14)2 = 22 = 4,
the sum is 32
The standard deviation = √(32/5) ≈ 2.5
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∙ 13y ago
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