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The formula for the standard deviation of a sample (s) is given by:
s =√(⅟₍n₌₁₎Σ(y-ȳ)²)
where y are the data points and ȳ is their mean; it can be rearranged to give:
s = √(⅟₍n₌₁₎(Σy² - n((Σy)/n)²)
→ s = √(⅟₍₅₌₁₎(1815 - 5(⁹⁵/₅)²)
→ s = √(¼ × 10)
→ s = √2.5
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How do you write 18 squared in standard form?
you do this by 18*18
What is a number divided by -9 decreased by 18 is -17?
The number is -9 because (-9/-9) -18 = -17
Write the number 18 as the sum of two primes?
1 + 17 = 18 5 + 13 = 18 7 + 11 = 18
8 9 12 13 16 17 18 which doesn't fit?
18
What is 17 divided by 7?
17 divide by 7 = 2.4285714285714284
What choices is the standard deviation of the sample shown here 17 18 19 20 21?
√2.5
What is the range of standard deviation of 18 15 12 13 17 14 19 20 8?
The range is 12 and the standard deviation is 3.822448314.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
Suppose that a population that a population has mean equals 64 and standard deviation equals 18. A sample of size 36 is selected. What is the mean of the sampling distribution of means?
64.
If the variance of the data values in a population is 324 what is the standard deviation of the data values?
Standard Deviation (SD) = sqrt(Variance(Var)) SD = sqrt(Var) Sd = sqrt(324) SD = 18
Find the range and standard deviation of the data set. 22 18 19 25 27 21 24?
The range is 9 and 3.01 is the standard deviation.
What is the mean absolute deviation of this set of numbers 3 9 27 81?
mean | 30 median | 18 standard deviation | 35.496
Is a standard deviation of 18 considered high?
The standard deviation, in itself, cannot be high nor low. If the same measurements were recorded using a unit that was a ten times as large (centimetres instead of millimetres), the standard deviation for exactly the same data set would be 1.8. And if they were recorded in metres the sd would be 0.018
The population standard deviation on a given measure of aggressive behavior equals 18 and you have 25 cases available for your assessment Calculate the standard error of the mean?
3.6
Construct an 80 percent confidence interval for the true population mean given that the standard deviation of the population is 6 and the sample mean is 18?
THe answer will depend on whether the confidence interval is central or one-sided. If central, then -1.28 < z < 1.28 -1.28 < (m - 18)/6 < 1.28 -7.68 < m - 18 < 7.68 10.3 < m < 25.7
How do you write 8 hundreds 17 tens and 18 ones in standard form?
8*100 + 17*10 + 18*1 = 800 + 170 + 18 = 988
Mean of taking a test is 22.3 minutes with a standard deviation of 2.8 minutes what probability will fall between 18 and 23.1 minutes?
Approx 0.55
