360 degrees. The sum of the measures of the exterior angles of any polygon is 360°.
Sum of exterior angles = 360 degrees Sum of interior angles = 1440 degrees
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
The sum of the exterior angles is always 360 degrees.
Sum of interior angles of n-sided polygon = 180n - 360 degrees. When n = 20 this gives 3240o
The sum of the exterior angles of a polygon is 360o.
A Regular Polygon
The sum of the exterior angles of any polygon is 360 degrees.
If you multiply 360 by the number of angles in the polygon and then subtract the sum of all the interior angles you will end up with the sum of all the exterior angles of the polygon.
The sum of the interior angles of a four-sided polygon is 360 degrees.
The sum of the exterior angles of any polygon is 360 degrees
The sum of the exterior angles of ANY polygon is 360 degrees.
It depends on what polygon you are referring to
The formula for the sum of the interior angles of a polygon is: 180 * (n - 2) where n is the number of sides of the polygon. So the sum of the angles of a polygon with 25 sides is 180 * 23 = 4,140.
(number of sides-2)*180 = sum of interior angles of a polygon
The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?
If the polygon has n sides, the sum of its interior angles is 180*(n-2) degrees.