Sum of interior angles of n-sided polygon = 180n - 360 degrees.
When n = 20 this gives 3240o
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The question can be answered only if the 20-gon is regular - ie all its angles are the same. IF that is the case, then: The sum of the exterior angles of any polygon is 360 degrees. Since there are 20 exterior angles, each of them must be 360/20 = 18 degrees.
A regular 18 sided polygon has 18 exterior angles each measuring 20 degrees
The interior angles of an n-sided polygon add to (n-2)*180 degrees. So the interior angles of a 20-gon add to 18*180 = 3240 degrees. The 20-gon is regular so each angle is a 20th of this ie 3240/20 = 162 deg.
There is a corresponding side to every angle. 20... A polygon has as many sides as it does angles.
A twenty-sided polygon is called an "icosagon" If it is a regular icosagon - all its sides and angles are equal - then it's interior angles are all 162 degrees. You can verify this by drawing a line to the centre from each angle.. There will be 20 small angles arranged in a circle around the centre. These must total 360 degrees. As 360 / 20 = 18, this leaves the other angles of each triangle to add up to 162, because the interior angles of a triangle total 180 degrees.