The sum of the cubes of the first 100 whole numbers is 25,502,500.
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First, let's find the sum of 100 terms, where a1 is 1 and an = 100. Sn = (n/2)(a1 + an) S100 = (100/2)(1 + 100) = 50(101) = 5,050 The average of all whole numbers from 1 to 100 is: 5,050/100 = 50.5
The first 100 even numbers are: 2 468101214161820222426283032343638404244464850525456586062646668707274767880828486889092949698100102104106108110112114116118120122124126128130132134136138140142144146148150152154156158160162164166168170172174176178180182184186188190192194196198200.
64 is the square of 8 and the cube of 4.
3. 14159265358979323846264338327950288419716939937510 58209749445923078164062862089986280348253421170679
The smallest such number is 100, the largest is 999, so the size of this set is:999 - 100 + 1 Another way to solve this: You have: * 9 options for the first digit * 10 options for the second digit * 10 options for the third digit Multiply all these numbers together.