Yes.
The whole part - all of it.
It depends on your definition of whole numbers. The classic definition of whole numbers is the set of counting numbers and zero. In this case, the set of whole numbers is not closed under subtraction, because 3-6 = -3, and -3 is not a member of this set. However, if you use whole numbers as the set of all integers, then whole numbers would be closed under subtraction.
The perfect numbers less than 100 are 6 and 28.
4x4=16, and 5x5=25, so 4 and 5 are the whole numbers closest to the square root of 19. [And incidentally of all the square roots of all the whole numbers between 16 and 25.]
50
101
Whole numbers between 1 and 100 are just counting numbers. Can you count? Just start at 1 and count to 100. All the numbers in your count will what you are asking for: That is: 1, 2,3, ... (fill in the missing numbers ) 98,99,100.
All numbers from 1 to 100 which are whole numbers are integers
5050
The total of all of the numbers from 1 to 99 is 4950.
It is 50.
No, they're not. The range from 100 to 1,000 includes numbers like 100.6, 239.07,5431/2, and 942.638, and those are not 'whole numbers'.But the numbers in that range that have nothing after the decimal point, and haveno fraction after them, are all whole numbers.The same is also true of any number that's notbetween 100 and 1,000 .
No. Factorials can only be placed on positive whole numbers or 0. For example, 0!, 1!, and 6! are all fine, but 2.5! and (-1)! are not. Since factorials can only be placed on whole numbers, that means you will only be multiplying whole numbers. 100! = 100 * 99 * 98 ... * 1; all those numbers are whole numbers, meaning your answer will be a whole number.
I wrote out all the factors of all the numbers from 1 to 100 and counted them.
302
The average is all the numbers added together and divided by how many numbers there are. In this case: 78+100=178. 178/2=89. Therefore the mean/average of the two numbers is 89.