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The first integer between 1 and 300 that is divisible by 11 is 11, the second is 12, the third is 33, ..., and the last one is 297 (27 x 11). So we can write the general form of nth term of this arithmetic sequence which is:

an = na1, where a1 is 11 and n = 1, 2, 3, ..., 27, and a27 = 297.

By substituting these values into the formula of the sum of the first nth terms of an arithmetic sequence we have:

Sn = (n/2)(a1 + an)

S27 = (27/2)(11 + 297) = (27/11)(308) = 27 x 154 = 4,158.

Thus, the sum of the integers between 1 and 300 is 4,158.

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15y ago
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Q: What is the sum of the integers between 1 and 300 that are divisible by 11?
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