Q: Sum of three consecutive integers is divisible by three?

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Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.

There is no set of three consecutive integers whose sum is 71.

The sum of three consecutive integers is -72

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

The three integers are 187, 188 and 189.

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Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.

Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.

There is no set of three consecutive integers whose sum is 71.

The sum of three consecutive integers is -72

Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43

There are no three consecutive odd integers who's sum equals 13.

No. There is no set of three consecutive even integers with a sum of 40.

20,21 and 22 are three consecutive integers whose sum is 63. 20+21+22

The sum of the squares of the three consecutive integers 11, 13, 15 = 515

The three integers are 187, 188 and 189.

The integers are -19, -18 and -17.

Here are some consecutive odd integers. All must follow this form: x+x+2+x+2=3x + 6 6 is divisible by 3. So is 3x. If you add two integers that are divisible by 3, it is still divisible by three. The question is not about odd integers, but consecutive integers. This should be x + x+1 + x+2 =3x+3 A bit simpler would be the three in a row : x-1, x, x+1 which add up to 3x which can be divided by 3.