1m*2m*15cm = 0.3 metres3 = 300 Litres
area = length x width = 20 x 15 = 300 sq cm
first find the unknown angle, 180o - (62o+62o) = 56o next use the law of sines to find the other side: sin 62o / 15cm = sin 56o / X Solving for x, X = 14.08 cm
15cm 12cm
Surface area of a cylinder = (pi) x (diameter of the circular end) x (length)
The surface area of a cylinder where height is 80cm and radius is 15cm equals 8953.54cm2
15 cm is a measure of length and a length has no surface.
1m*2m*15cm = 0.3 metres3 = 300 Litres
The surface area of a box 15cm x 12cm x 8 cm is 2 times 15cm times 12cm, plus 2 times 15cm times 8 cm, plus 2 time 12cm times 8 cm, or 792cm2. However, this is only the surface area - the actual wrapping paper required would depend on the method of wrapping and how much overlap is desired. Since you would not want to splice the paper, you certainly would need more that 792cm2 but, again, that depends on your wrapping style.
34 cm
Let x be the length of one of the congruent sides, then the three sides are x, x, 3x. Perimeter = x + x + 3x = 5x = 75cm => x = 15cm Thus the three sides are 15cm, 15cm, 45cm.
answer me
(1/5) x 15 = 3 cm
Perimeter is the total of all the sides. Let's assume your part-question relates to a rectangle. Four sides: 2 x 8cm and 2 x 15cm. I'm sure you can work it out from there...
5cm x 3cm x 15cm = 225 cm3
252π cm2 ≈ 791.68 cm2 Surface area = area end + area_side + area_end = 2 x (area_end) + (height x circumference_of_end) = 2 x (π x radius2) + (height x 2 x π x radius) = 2 x π x radius x (radius + height) = 2 x π x 6 cm x (6 cm + 15 cm) = 252π cm2 ≈ 791.68 cm2
It is: 2+15+2+15 = 34cm