Assuming that 15 and 12.5 units are measures of the lengths of two sides of the triangle, the third is any value in (2.5, 27.5) units
For a triangle to exist, the sum of the two shorter sides must be longer than the longest side. If 15 is the longest side, then the other, missing, shorter side must be greater than 15 - 4 = 11. If the third, missing, side is the longest side, then it must be less than 15 + 4 = 19 So the third side is any length greater than 11 and less than 19. Examples include 12, 13, 15, 11.5, 18.5.
The third side must be longer than 11 and shorter than 19.
No. The sum of the lengths of any two sides of a triangle must be greater that the third. Here 6 + 9 = 15, not > 15.
Call the two equal sides 2x and the third side x+4: 2x+x+4 = 49 2x+x = 49-4 3x = 45 x = 15 So the length of two equal sides are 15 ft each and the larger side is 19 ft (Incidentally the garden is in the shape of an isosceles triangle)
Let the shortest side be x cm, so that the longest side is 2x cm, and the third side is x + 7 cm. Since the perimeter of the triangle is 39 cm we have:x + 2x + x + 7 = 394x = 32x = 8Thus, the lengths of the sides are 8 cm, 15 cm, and 16 cm.
This would be an isosceles triangle.
Any number between 3 and 15
For a triangle to exist, the sum of the two shorter sides must be longer than the longest side. If 15 is the longest side, then the other, missing, shorter side must be greater than 15 - 4 = 11. If the third, missing, side is the longest side, then it must be less than 15 + 4 = 19 So the third side is any length greater than 11 and less than 19. Examples include 12, 13, 15, 11.5, 18.5.
The third side must be longer than 11 and shorter than 19.
Since there is no triangle "below", all that can be said is that EF - if it is the third side of the triangle - is any length in the interval (24, 54).
No. The sum of any two sides of a triangle MUST be greater than the third side. 9 + 4 is 13 which is not greater than 15.
11 centimeters 15 centimeters and 17 centimeters can form a triangle . It is because some of any two sides of triangle is greater than the third side . a + b >c always.
9 cm or 19.209 cm, solved by using Pythagoras' theorem.
Line segments of lengths 94 and 15 could form a triangle provided the third side was in the range (79, 109).
To create a triangle, the sum of the two shorter sides must be greater than the third side. If the side of length 9 is the longest side then the missing side must be greater than 9 - 6 = 3 If the missing side is the longest side then the missing side must be less than 6 + 9 = 15 Thus any length that is greater than 3 and less than 15. Examples include: 10, 4, 7, 12
It could be 12 because the sum of the 2 smaller sides of a triangle must be bigger than its largest side.
The sum of the two shorter sides of a triangle must be longer than the third. Thus the third side can be any length greater than 0 and less than 20. Examples are 0.5, 2, 5, 10, 15, 17.5, 19.9.