If you mean: y = 3x+1 then the value of y will equal 10
That factors to 3x(3x - 1)
If: 3x-1 = 11 Then: 3x = 11+1 So: x = 12/3 = 4
3x - x = (3 - 1)x = 2x
(1, -1)
If: 5-3x = x+1 then the value of x = 1
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
The minimum value of the parabola is at the point (-1/3, -4/3)
- If 3X - 1 = 11, what is the value of X^2 + X?
1
1
X = -2(13 + y) / 3x = 5y / 4 - 1
this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7
3x2 - 2x - 5 = (3x - 5)(x + 1) = 0 gives a solution of x = 5/3 or -1. Was that what you wanted?
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
If 3x - 1 = 11 what is the value of x 2 + x?
If you mean: y = 3x+1 then the value of y will equal 10