That factors to 3x(3x - 1)
(3x + 8)(3x - 8)
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
9x^(2) - 49 Re-write as two squared terms. (3x)^(2) - 7^(2) This will factor to ( 3x - 7)(3x + 7) Note the two different signs.
3x squared minus 25x minus 28
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
9x2-9x-10 = (3x+2)(3x-5) when factored
(3x + 8)(3x - 8)
9x^(2) - 49 Re-write as two squared terms. (3x)^(2) - 7^(2) This will factor to ( 3x - 7)(3x + 7) Note the two different signs.
This is a difference of two squares, which factorises to: (3x - 4y)(3x + 4y)
(x + 2)(3x - 1)(3x + 1)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)
9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)
3x squared minus 25x minus 28
3
9x^(2) - 16 This can be written as two squared terms. Hence (3x^(2) - 4^(2) Remember two squared terms with a negative(-) between them will factors. Hence (3x - 4)(3x + 4) Note the two different signs.
x2-9x can be factored by taking x out of each term x(x-9)
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared