It is 138.
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
A constant is a value that never changes such as 4, 6.5, 3/4, pi, or the square root of 5. This is different from a variable where the value varies like x. In the expression 5x, 5 is a constant and x is a variable.
5X - 2Y X = 9 Y = 4 5(9) - 2(4) 45 - 8 37 is the value
(2\5)
To write "5 subtracted from a quarter of s" as an expression, you can first express a quarter of s as s/4, and then subtract 5 from it. The expression would be s/4 - 5.
-4 (-9 +5 = -4)
51 × 14 = 5/4 54
How can we know? You do not list the expressions "below". At a guess, if one of them is 0.8333(recurring) then it is that one.
Say you have an algebraic expression y = 3x +4 For a given value of x = 5 substitute that number in place of x in the expression, so in this case y = 3(5) + 4 = 19
To find the value of the expression 4 - 5 + 6 - 7 - (-4), we can simplify it step by step: First, let's simplify the expression within the parentheses (-4): -(-4) is equivalent to adding 4, so -(-4) becomes +4. Therefore, the expression becomes: 4 - 5 + 6 - 7 + 4. Next, let's perform the addition and subtraction from left to right: 4 - 5 = -1 -1 + 6 = 5 5 - 7 = -2 -2 + 4 = 2. Therefore, the value of the expression 4 - 5 + 6 - 7 - (-4) is 2.
To find the value of the expression 4x - 2y + xy when x = -1 and y = 5, we first substitute the values of x and y into the expression. This gives us 4(-1) - 2(5) + (-1)(5). Simplifying this further, we get -4 - 10 - 5, which equals -19. Therefore, the value of the expression is -19 when x = -1 and y = 5.
Just substitute 4 in for X. 13 - 2(4) 13 - 8 = 5 ===
The expression IS 5*4 - 8.
The vertex of this parabola is at -5 -2 When the x-value is -4 the y-value is 2. The coefficient of the squared expression in the parabola's equation is 4. y = a(x - h)2 + k; (h, k) = (-5, -2); (x, y) = (-4, 2) 2 = a[-4 -(-5)]2 - 2, add 2 to both sides 4 = a(-4 +5)2 4 = a(1)2 4 = a
write it 5 times
-3
-3