Well, let's bring some peace and calmness to this math problem. To find the value of y, we first need to isolate it. We can start by adding 5 to both sides of the equation, then dividing by 8 to solve for y. Remember, there are no mistakes in math, just happy little accidents.
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To find the value of y in the equation 8y - 5 = 11, you need to isolate y. Start by adding 5 to both sides of the equation to get 8y = 16. Then, divide both sides by 8 to solve for y, which gives you y = 2. Therefore, the value of y in the equation is 2.
Oh, dude, you just gotta isolate that y to find its value. So, first, add 5 to both sides to get 8y = 16. Then, divide by 8 to find y = 2. Easy peasy lemon squeezy.
5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
No, that is a equation.
If x=6 and y=8, then [ 5x + 8y ] = 5(6) + 8(8) = 30 + 64 = 94
x + 4y = 5Standard Form for a linear equation is Ax + By = C, where B is not = 0, A is >=0, A is an integer, and -preferably- A, B and C have no common factor. Sometimes ax + by + c = 0 is used instead.10 - 2x = 8y 10-2x-8y =0 -2x-8y=-10 2x+8y=10 x+4y=5.
3y - 20 = 8ySubtract 3y from each side:-20 = 5yDivide each side by 5:-4 = y