8x = 6y (8/6)x = y (4/3)x = y Let x = 3, 6, and 9, then y = 4, 8, and 12. So that for any value of x, you will find a correspoinding value for y.
y is 2/3.
If you mean: -9x+4y = 8 and -3x+y = 4 then the solutions are x = -8/3 and y = -4
x+y=12 x-y =4 x=12-4 =8 8+y=12 y=12-8 =4 so x=8 y=4 8+4=12 8-4=4
x = 8y = -42x - y = 2(8) - (-4) = 16 + 4 = 20
if y = 5x – 8 find the value of x if y = 7
11
Add 8 to the x value, so f.e. If x=4, the y intercept = 4+8 =12 No, the y intercept is the value of y when the value of x = 0, so the y intercept of the equation is 8. In the general form y = mx + b, b will always be the y intercept.
x+y = 10 and y = x+8 x+x+8 = 10 x+x = 10-8 2x = 2 x = 1 Substitute the value of x into the original equations to find the value of y: So: x = 1 and y = 9
8x = 6y (8/6)x = y (4/3)x = y Let x = 3, 6, and 9, then y = 4, 8, and 12. So that for any value of x, you will find a correspoinding value for y.
14
2x+y = 8 y = -x+5 Substitute y for -x+5 into the first equation: 2x+(-x+5) = 8 2x-x+5 = 8 x = 8-5 x = 3 Substitute the value of x into the original equations to find the value of y: x = 3 and y = 2
the value is 20
Since the relationship between x and y is not defined, x can have any value whatsoever.
y is 32.
y is 2/3.
y=8 y = 2x y = 2(4) <-- substitute 4 for x y = 8 <-- this is your answer