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distance = 1/2 gt^2 wher g is acceleration of gravity on moon = about 5 ft/sec/sec

35 = 2.5t^2

t^2 = 14

t = 3.74 seconds

velocity = at = 5 x 3.74 = 18.7 feet/second

the mass of the rock does not enter into this

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Q: What is the velocity of a five kilogram rock when it strikes the surface of the moon after falling thirty-five feet?
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