Best Answer

Velocity final = vi + at = 49 m/s

displacement = vi * t + ½2at² = 122.5 m

vi = 0

a ≈ 9.8

t = 5

Q: A marble dropped from a bridge strikes the water in 5 seconds. What is the speed with which it strikes and the height of the bridge?

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19.6 meters / 64.4 ft

depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.

Distance of fall in T seconds = 1/2 g T2Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 metersHeight of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters

a. 144 feet b. 96 ft/sec.

Assuming that seconds refers to the period, the frequency is the reciprocal (1 / period in seconds). The height of the wave is irrelevant in this case.

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The initial velocity of the marble is 0 m/s (dropped). Using the equation for free fall: h = 0.5 * g * t^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is time (5 seconds), we can find the height of the bridge. The speed at which the marble strikes the water can be calculated using the equation: v = g * t.

Assuming the stone was dropped from rest, we can calculate the height of the bridge using the kinematic equation: h = 0.5 * g * t^2, where h is the height of the bridge, g is the acceleration due to gravity (9.8 m/s^2), and t is the time of fall (2.1 seconds). Plugging in the values, we get h = 0.5 * 9.8 * (2.1)^2 = 22.33 meters. Therefore, the height of the bridge is approximately 22.33 meters.

Neglecting air resistance . . .The acceleration of gravity is 9.8 meters (32.2 feet) per second2.After 5 seconds the marble's downward speed is (9.8 x 5) = 49 meters (160.8-ft) per second.Its average speed during the fall is (49/2) = 24.5 meters (80.4-ft) per second.The distance it falls is (24.5 x 5) = 122.5 meters (402-ft).

If we assume the time it takes for the ball to stop is directly proportional to the height it is dropped from, we can set up a proportion based on the given information. From the given data, we have the ratio of time to height as 11/1 = 25/2. Therefore, if we continue this ratio, the time it would take to stop if dropped from 3 feet would be 55 seconds.

The height of the bridge can be calculated using the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the rock takes 8 seconds to hit the water, the height of the bridge would be approximately 313.6 meters.

19.6 meters / 64.4 ft

depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.

The rebound height of a dropped bouncy ball is generally lower than the dropped height due to energy losses from deformation and air resistance. However, for ideal elastic collisions, the rebound height is approximately equal to the dropped height.

distance = speed x time so the distance is just the speed of the stone x 8 seconds

The height of the building at the 102nd floor is 381 metres. The penny is irrelevant.

The height of the building at the 102nd floor is 381 metres. The penny is irrelevant.

Gravity = 9.8 meters per second