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your question is unclear
We can make some assumptions though.
If you talk about a piece of wood, then the scale is most likely Inches.
That would mean that you have a unspecified length of wood that is 6 inches wide and 2 inches thick.
If however talking about steel, then the measurement is probably in Centimeters. An unspecified length of steel/iron that is 2 centimeters thick and 6 centimeters wide. This would probably be a hollow length of some material.
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How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
The length of a rectangle is 3 more than twice its width The perimeter is 48 feet what is the width?
Call the width x and the length 3x.Write an equation for perimeter: 3x+3x+x+x=48Simplify: 8x=48Divide: x=6Plug in 6 for x, therefore the width of the rectange is 6.
The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
The length of a rectangle is twice its width If the perimeter is 84cm what are the dimensions of the rectangle?
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
A package of aluminum foil contains 53 ft2 of foil which weighs approximately 7.2 oz Aluminum has a density of 2.70 gcm3 What is the approximate thickness of the foil in millimeters?
53ft2=49,238.6112sq cm 7.2 oz=204.1165665g density of aluminum=2.7g/cm3 (volume=mass/density) v=75.59872833cm3 volume=length x width x thickness 75.59872833= 49238.6112 x thickness thickness= 0.00154cm
