0
your question is unclear
We can make some assumptions though.
If you talk about a piece of wood, then the scale is most likely Inches.
That would mean that you have a unspecified length of wood that is 6 inches wide and 2 inches thick.
If however talking about steel, then the measurement is probably in Centimeters. An unspecified length of steel/iron that is 2 centimeters thick and 6 centimeters wide. This would probably be a hollow length of some material.
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How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
The length of a rectangle is 3 more than twice its width The perimeter is 48 feet what is the width?
Call the width x and the length 3x.Write an equation for perimeter: 3x+3x+x+x=48Simplify: 8x=48Divide: x=6Plug in 6 for x, therefore the width of the rectange is 6.
The length of a rectangle is 6 inches more than twice its width If the perimeter of the rectangle is 54 inches find the width of the rectangle?
Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)
The length of a rectangle is twice its width If the perimeter is 84cm what are the dimensions of the rectangle?
Let the length be 2x and the width be x: Perimeter = 2(2x+x) = 84 4x+2x = 84 6x = 84 Divide both sides of the equation by 6 to find the value of x: x = 14 Therefore: length = 28cm and width = 14cm
A package of aluminum foil contains 53 ft2 of foil which weighs approximately 7.2 oz Aluminum has a density of 2.70 gcm3 What is the approximate thickness of the foil in millimeters?
53ft2=49,238.6112sq cm 7.2 oz=204.1165665g density of aluminum=2.7g/cm3 (volume=mass/density) v=75.59872833cm3 volume=length x width x thickness 75.59872833= 49238.6112 x thickness thickness= 0.00154cm
How to calculate surface area of flat bar?
If the bar is a three dimensional object it will have some thickness. Then, assuming it is oblong in shape and knowing its length, width and thickness: Surface_area = 2 x (length x width + width x thickness + thickness x length)
What is the standard sizes of hollow block in Philippines?
The hollow block sizes in the Philippines are the following:40cm (length) X 20 cm (width) X 4 in (thickness)40cm (length) X 20 cm (width) X 5 in (thickness)40cm (length) X 20 cm (width) X 6 in (thickness
What is weight calculation formula of channel?
{2 x Height + Width - 2 x Thickness} (MM) x Length (MTR) x Thickness (MM) x {0.7843 x 0.01}
What is the Concrete hollow block size in the Philippines?
The hollow block sizes in the Philippines are the following:40cm (length) X 20 cm (width) X 4 in (thickness)40cm (length) X 20 cm (width) X 5 in (thickness)40cm (length) X 20 cm (width) X 6 in (thickness)
The length of a rectangle is two times its width. If the perimeter of the rectangle is 48 what is its area?
length = 2 x width Perimeter = 2 x (length x width) =2 x (2 x width + width) = 2 x (3 x width) = 6 x width → 6 x width = 48 units → width = 48 units ÷ 6 = 8 units → length = 2 x width = 2 x 8 units = 16 units Ares = length x width = 16 units x 8 units = 128 square units
What is thickness of 2 x 6?
12
What diameter round wire does it take to produce a flat wire of predetermined width and thickness?
The required diameter is 2 times the square root of ( width x thickness / pi )
What is the formula for weighing metals by its size Length x Width x Thickness?
Density = Mass / Volume the Volume is what you just said ... length x width x thickness
How much would a piece of amber 3 inch lenghth 2 inch width worth?
6 x (thickness of the piece) x (value of one cubic inch of amber)
What Sides of a rectangle give perimeter equal to to area?
perimeter = 2 x (width + length) area = width x length If area = perimeter then: width x length = 2 x width + 2 x length width x length - 2 x length = 2 x width length x (width - 2) = 2 x width length = 2 x width / (width - 2) So any rectangle with length and width that satifies the above will work, for example: width = 2.5, length = 10, area: 2.5 x 10 = 25; perimeter: 2x(2.5+10) = 2x12.5 = 25 width = 3, length = 6, area: 3x6 = 18; perimeter: 2x(3+6) = 2x9 = 18 width = 4, length = 4, area: 4x4 = 16; perimeter: 2x(4+4) = 2x8 = 16 By making the length dependent on the width, the width must be at least 2. Once the 4x4 square has been reached, the width becomes larger than the length, but the pair will also be given if the width is the smaller dimension, for example, a width of 6 gives a length of 2 x 6 / (6 - 2) = 12 / 4 = 3, which matches the length of 6 being given by a width of 3.
What is the volume of a box that has a height of 6 width of 9 and a length of 2?
Volume is equal to height x width x length, therefore, the answer is 6 x 9 x 2 which equals 108.
How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
