length*width = area 24.7*width = 550.81 Divide both sides by 24.7 to find the width: width = 22.3 meters
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
Well, darling, the volume of a chalkboard eraser can vary depending on its shape. If it's a rectangular prism, you can calculate it by multiplying the length, width, and height in centimeters. If it's a cylindrical eraser, you can use the formula for the volume of a cylinder. Just grab a ruler and measure that bad boy to get your answer!
There are many things that can be measured in millimeters:- paper clips- width of an eraser- length of an eraser- length and width of a simple battery- length of a pencil lead- width of a switch in which we plug things- beads- fingernails- width of a small can- eyelashes- wire diameters- tube diameters- the buttons on a monitor, on a CPU or on a laptop- icons that appear on a monitor screen
Six millimeters is roughly the size of the tip of a pencil eraser or the width of a standard paperclip. It is a small measurement, about the width of a grain of rice.
No, it doesn't have a definite volume or definite shape
You can measure small lengths in millimeters. Length of a pencil, pen, eraser, length and width of a paper, sheet etc. can be measured in millimeters.
The eraser poem the eraser poe the eraser po the eraser p the eraser the erase the eras the era the er the e the th t .
erase something and get the shavings from the eraser and melt them together and you are done
in 1770 the eraser was made
The plural of eraser is erasers.
Friction causes the eraser to become warm.
a pen eraser is an eraser which can rub out either cartridge pen or an ink pen.
The eraser costs 1.50.