Yes, the word 'equation' is a noun, a word for a thing.
Domain is the independent variable in an equation. It is what you put "in" the equation to get the Range.
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The abstract noun forms of the verb to 'equate' are equation and the gerund, equating (a word for a process).The noun 'equation' is an abstract noun as a word for the process of considering one thing to be the same as another; a word for a concept.The noun 'equation' is a concrete noun as a word for a statement with two sets of numbers, letters, or symbols are equal; a word for a written or spoken statement.
Equation
The balanced chemical equation for when barium chloride (BaCl2) reacts with sodium sulfate (Na2SO4) is: BaCl2 + Na2SO4 -> BaSO4 + 2NaCl.
The balanced equation for barium chloride (BaCl2) reacting with sodium sulfate (Na2SO4) to form barium sulfate (BaSO4) and sodium chloride (NaCl) is: BaCl2(aq) + Na2SO4(aq) -> BaSO4(s) + 2NaCl(aq).
The reaction between sodium sulfate (Na2SO4) and barium chloride (BaCl2) results in the formation of solid barium sulfate (BaSO4) and a solution of sodium chloride (NaCl) as per the double displacement reaction: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
To balance the chemical equation between BaCl2 and Na2SO4, you need to ensure that the number of each type of atom is the same on both sides of the equation. The balanced equation is BaCl2 + Na2SO4 -> BaSO4 + 2NaCl.
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
To find the volume of BaCl2 needed to react completely, use the stoichiometry of the balanced equation. First, calculate the moles of Na2SO4 using its provided concentration and volume. Then, use the balanced equation to determine that it reacts in a 1:1 ratio with BaCl2. Finally, convert the moles of Na2SO4 to volume of BaCl2 using its molarity. The correct volume should be found as 145 mL.
To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.
To find the limiting reagent, first calculate the moles of barium chloride and sodium sulfate. Then, based on the balanced chemical equation, determine which reagent will run out first. Use the limiting reagent to calculate the moles of barium sulfate formed, and finally convert this to grams using the molar mass of BaSO4.
The chemical equation for the reaction of sodium sulfate with barium chloride is: Na2SO4 + BaCl2 → 2NaCl + BaSO4. This is a double displacement reaction where the sodium and barium ions switch partners to form sodium chloride and barium sulfate.
Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS
When BaCl2 (barium chloride) is added to Na2SO4 (sodium sulfate), a precipitation reaction occurs, resulting in the formation of a white precipitate of barium sulfate (BaSO4). This is represented by the chemical equation: BaCl2 + Na2SO4 → BaSO4 + 2NaCl.
Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.