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barium chloride plus sodium sulphate yields barium sulphate plus sodium chloride

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Ahmedi Othman

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9mo ago

Barium chloride + sodium sulphate to form barium sulphate + sodium chloride

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Q: What is the word equation for BaCl2 Na2SO4?
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What is the balanced chemical equation for when barium chloride reacts with sodium sulfate?

The balanced chemical equation for when barium chloride (BaCl2) reacts with sodium sulfate (Na2SO4) is: BaCl2 + Na2SO4 -> BaSO4 + 2NaCl.


What is the balanced equation of barium chloride and sodium sulfate include phases?

The balanced equation for barium chloride (BaCl2) reacting with sodium sulfate (Na2SO4) to form barium sulfate (BaSO4) and sodium chloride (NaCl) is: BaCl2(aq) + Na2SO4(aq) -> BaSO4(s) + 2NaCl(aq).


What is the reaction for Na2SO4 BaCl2?

The reaction between sodium sulfate (Na2SO4) and barium chloride (BaCl2) results in the formation of solid barium sulfate (BaSO4) and a solution of sodium chloride (NaCl) as per the double displacement reaction: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl


How do you balance BaCl2 and Na2SO4?

To balance the chemical equation between BaCl2 and Na2SO4, you need to ensure that the number of each type of atom is the same on both sides of the equation. The balanced equation is BaCl2 + Na2SO4 -> BaSO4 + 2NaCl.


What is the balanced equation for Barium Chloride plus Sodium Sulfate?

Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4


What volume of 0.131 M BaCl2 is required to react completely with 42.0 ml of .453 MNa2SO4. This is the net ionic equation for the reaction. Ba2 plus plus SO42---- BaSO4. Correct answer equals 145 ML?

To find the volume of BaCl2 needed to react completely, use the stoichiometry of the balanced equation. First, calculate the moles of Na2SO4 using its provided concentration and volume. Then, use the balanced equation to determine that it reacts in a 1:1 ratio with BaCl2. Finally, convert the moles of Na2SO4 to volume of BaCl2 using its molarity. The correct volume should be found as 145 mL.


If 57.0 mL of BaCl2 solution is needed to precipitate all the sulfate ion in a 742 mg sample of Na2SO4 what is the molarity of the solution?

To find the molarity of the BaCl2 solution, first calculate the moles of Na2SO4 in the sample using its molar mass. Then, use the balanced chemical equation of the precipitation reaction to determine the moles of BaCl2 needed to react with the moles of Na2SO4. Finally, divide the moles of BaCl2 by the volume of the solution in liters (57.0 mL = 0.057 L) to find the molarity.


How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?

To find the limiting reagent, first calculate the moles of barium chloride and sodium sulfate. Then, based on the balanced chemical equation, determine which reagent will run out first. Use the limiting reagent to calculate the moles of barium sulfate formed, and finally convert this to grams using the molar mass of BaSO4.


What is the Chemical equation for the reaction of Sodium Sulphate with Barium Chloride?

The chemical equation for the reaction of sodium sulfate with barium chloride is: Na2SO4 + BaCl2 → 2NaCl + BaSO4. This is a double displacement reaction where the sodium and barium ions switch partners to form sodium chloride and barium sulfate.


What is the balanced equation for sodium sulfate plus barium chloride yields barium sulfate and sodium chloride?

Ooh. Somebody doesn't like doing their chem homework. Luckily I just happened to do that exact same equation. 1 BaCl2 +1 Na2S --> 2 NaCl(Salt! :D) +1 BaS


An aqueous solution BaCl2 is added to NaSO4 what reaction occurs?

When BaCl2 (barium chloride) is added to Na2SO4 (sodium sulfate), a precipitation reaction occurs, resulting in the formation of a white precipitate of barium sulfate (BaSO4). This is represented by the chemical equation: BaCl2 + Na2SO4 → BaSO4 + 2NaCl.


What is the name of the balanced equation of barium chloride and sodium sulfate?

Barium Chloride + Sodium Sulfate --> Barium Sulfate + Sodium Chloride BaCl2 + Na2So4 --> BaSO4 + 2NaCl It's called a Double Displacement reaction because Barium(Ba2+) and Sodium(Na+) displaces each other from their original anions. It's also called a Precipitation reaction because a white precipitate is formed after the reaction due to Barium Sulfate(BaSO4) as it is insoluble.