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So, is that to say that 2x-y-2 = 0?

Taking into consideration that y = mx + b ...

2x-2 = y

y = 2x -2

In y = mx + b,

the "b" is the y intercept

the "m" is the slope

To find the x intercept, make y = 0 and solve.

0 = 2x -2

2 = 2x

x = 1

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Q: What is the x-intercept of 2x-y-2?
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