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The sum of two number is sixthe sum of the squares of the two number is twenty?
x+y=6x^2 + y^2=20 x=2 and y=4 or vice versa
What are the factors and prime factors of 16 xy?
1, 2, 4, 8, 16, x, y 2 is prime.
Number with the most factors?
This question doesn't have an actual answer. Here's why: We have a value X (doesn't matter what it equals). pick any integer greater than one (i'll choose 3) Y = 3*X now Y has all the factors of X , and then one more. Example: X=15 (15 = 3*5, so 2 factors) Y = 3*X (45 = 3*3*5, 3 factors (2 unique)) If you want a number with the most 'unique' factors, that doesn't work either. Just make sure the number you pick (my 3 in this case) is not factor of X to begin with. Example: I'll chose 2 this time because 2 is not a factor of 15. X=15 (15=3*5, 2 factors) Y=2*X (30= 2*3*5, 3 factors (all unique))
How do you factor 6x-6y?
6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
Two prime numbers have a sum of 54 and a difference of 20 What are the numbers?
x+y=54 x-y=20 solving it,we get x=37 and y=17
What pair of square numbers has a difference of 300?
The pair of square numbers that has a difference of 300 can be found by solving the equation (x^2 - y^2 = 300), which factors to ((x - y)(x + y) = 300). The factors of 300 can be paired to find suitable values for (x) and (y). One solution is (x = 19) and (y = 11), as (19^2 - 11^2 = 361 - 121 = 240). Another solution is (x = 20) and (y = 10), since (20^2 - 10^2 = 400 - 100 = 300).
What two numbers added together make7 but multiplied make 20?
Let call them x and y x+y=7 and x*y=20 From the first you get x = 7 -y, put into the second get (7-y)*y=20 -y^2+7*y=20 or y^2-7+20=0 Delta = (-7)^2-4*1*20 = -31 y = (7-i*sqrt(31))/ 2 or y = (7+i*sqrt(31))/ 2 and x = 7-y = (7+i*sqrt(31))/ 2 or x = (7-i*sqrt(31))/ 2
The sum of two numbers is 20 One number is two less than twice the ammount of the first number what are the two numbers?
x+y=20 x=2y-2 2y-2+y=20 y-2=20 y=18 x=2
The difference between two numbers is 20 and their sum is 48 Find the numbers?
x=number 1, y=number 2 {x-y=20} {x+y=48} x=y+20 y+20+y=48 2y=28 [y=14] x=14+20 [x=34]
The sum of two numbers is 16 and the difference is 20?
Let the two numbers be x and y since their sum is 16 x+y=16 since their difference is 20 x-y=20 so since x+y=16 x=16-y and now plug this in below 16-y-y=20 and 16-2y=20 -2y=4 y=-2 and x-2=16 so x=18 the numbers are 18 and -2
What are the x-intercepts of y equals 2x2 - 3x - 20?
y = 2x2 - 3x - 20 ∴ y = 2x2 - 8x + 5x - 20 ∴ y = 2x(x - 4) + 5(x - 4) ∴ y = (2x + 5)(x - 4) The x intercepts occur when y = 0, which happens when either of the two factors on the left side of the equation equal zero. This means that they are at the points (-5/2, 0) and (4, 0).
What is x when y is 30 if x is 20 when y is 40?
x and y are in a ratio of 1:2 so when y is 30 x is 15
What are the points of contact between the line 2y -x equals 0 and the curve x squared plus y squared equals 20?
If: 2y-x = 0 Then: 4y^2 = x^2 If: x^2 +y^2 = 20 Then: 4y^2 +y^2 = 20 So: 5y^2 = 20 Dividing both sides by 5: y^2 = 4 Square root of both sides: y = - 2 or + 2 By substituting points of contact are at: (4, 2) and (-4, -2)
What are the factors of a polynomial function with zeros at -2 and 7?
Since there are two zeros, we have: y = (x - (-2))(x - 7) y = (x + 2)(x - 7)
What is the definition of difference of squares?
It is one number or variable squared subtracted from another Such as x^2-y^2 since this factors as (x-y)(x+y)
What pair of square numbers makes a difference of 80?
Let's denote the two square numbers as x^2 and y^2. The difference between two square numbers can be expressed as (x^2 - y^2), which can be factored into (x + y)(x - y). Since the difference is 80, we have (x + y)(x - y) = 80. The factors of 80 are 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80. By testing out different combinations of these factors, we find that the pair of square numbers that make a difference of 80 is 82^2 and 2^2.
Solution set of y equals x2 - x - 6?
-4
