20xy2 = 225xy2 so the factors are
1 x y xy y2
2 2x 2y 2xy 2xy2
4 4x 4y 4xy 4y2
5 5x 5y 5xy 5y2
10 10x 10y 10xy 10y2
20 20x 20y 20xy 20y2
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1, 2, 4, 8, 16, x, y 2 is prime.
x+y=6x^2 + y^2=20 x=2 and y=4 or vice versa
This question doesn't have an actual answer. Here's why: We have a value X (doesn't matter what it equals). pick any integer greater than one (i'll choose 3) Y = 3*X now Y has all the factors of X , and then one more. Example: X=15 (15 = 3*5, so 2 factors) Y = 3*X (45 = 3*3*5, 3 factors (2 unique)) If you want a number with the most 'unique' factors, that doesn't work either. Just make sure the number you pick (my 3 in this case) is not factor of X to begin with. Example: I'll chose 2 this time because 2 is not a factor of 15. X=15 (15=3*5, 2 factors) Y=2*X (30= 2*3*5, 3 factors (all unique))
6x-6y=6(x-y) The factors of 6(x-y) are 6 and (x-y).
x+y=54 x-y=20 solving it,we get x=37 and y=17