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Q: What is the slope-intercept form of the equation -2x 5y-15?

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2x+3y-5=0

As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x

2x+5y = 10 5y = -2x+10 y = -0.4x+2 which is now in slope intercept form

what is the algebraic equation for 2x + 3 =8

Without an equality sign and no square variable the given terms can not be that of a quadratic equation.

Related questions

y = 2x + 1.

Get in form.2X - 5Y = 15- 5Y = - 2X + 15Y = (2/5)X - 3-------------------------Y intercept = - 3===============zero out Y to find X intercept(2/5)X - 3 = 0(2/5)X = 3X = 15/2------------X intercept = 15/2=============

slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form

2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8

2x+3y-5=0

2

It depends on what you are calling "standard form". 2x = 7 can be solved, but it is a standard form of an algebraic equation.

If you mean 2x-y = 8 then y = 2x-8

If you mean -2x+y = 8 then y = 2x+8 as a straight line equation

9

If you solve such an equation for "y", you get an equation in the slope-intercept form.

As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x

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