x² = x+110 x²-x-110 = 0 x1= -(-1/2) - Square root of ((1/2)²+110) x1 = 0.5 - 10.5 x1 = - 10 x2 = -(-1/2) + Square root of ((1/2)²+110) x2 = 0.5 + 10.5 x2 = 11
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x=-11 OR x=10 So, x2+x=110, or x2+x-110=0. Use the quadratic formula to solve for x x=((-1)+/-sqrt((-1)2-4*(1)(-110)))/(2(1)) x=((-1)+/-sqrt(441))/(2) x=((-1)+/-21)/(2) x=-22/2 OR x=20/2 x=-11 OR x=10 Alternatively, you can recognize that x2+x-110=0 can be factored into (x+11)(x-10)=0, which yields the same result.
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
(x+3)(x+4) = x2+7x+12
If: x^2 +18x = 29 Then completing the square: (x+9)^2 -81 = 29 or (x+9)^2 = 110
100x - 89x = 11011x = 110x = 110/11x = 10