x=-11 OR x=10 So, x2+x=110, or x2+x-110=0. Use the quadratic formula to solve for x x=((-1)+/-sqrt((-1)2-4*(1)(-110)))/(2(1)) x=((-1)+/-sqrt(441))/(2) x=((-1)+/-21)/(2) x=-22/2 OR x=20/2 x=-11 OR x=10 Alternatively, you can recognize that x2+x-110=0 can be factored into (x+11)(x-10)=0, which yields the same result.
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
(x+3)(x+4) = x2+7x+12
If: x^2 +18x = 29 Then completing the square: (x+9)^2 -81 = 29 or (x+9)^2 = 110
100x - 89x = 11011x = 110x = 110/11x = 10
x2 + 6x - 110 = 0 ∴ x2 + 6x = 110 ∴ x2 + 6x + 36 = 146 ∴ (x + 6)2 = 146 ∴ x + 6 = ±1461/2 ∴ x = -6 ±1461/2 ∴ x ≈ 6.083, 18.083
x(x + 1)
x2 + 10x + 21 = (x + 3)(x + 7)
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
x2 + x - 30 = (x + 6)(x - 5)
x(x+4) equals x2 plus 4x
x2 + 2
x2 + 2x - 15 = (x - 3)(x + 5)
if x2 + 7 = 37, then x2 = 29 and x = ±√29
X2 or 2 times x?
x = 2