x=-11 OR x=10
So, x2+x=110, or x2+x-110=0. Use the quadratic formula to solve for x
x=((-1)+/-sqrt((-1)2-4*(1)(-110)))/(2(1))
x=((-1)+/-sqrt(441))/(2)
x=((-1)+/-21)/(2)
x=-22/2 OR x=20/2
x=-11 OR x=10
Alternatively, you can recognize that x2+x-110=0 can be factored into (x+11)(x-10)=0, which yields the same result.
X = √63
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
(2, -2)
If I have this correct you are asking x^2 + 10^2 = 12^2 Then x=6.633249507108
100x - 89x = 11011x = 110x = 110/11x = 10
X = √63
89
x^2 + x = 110. x(x + 1) equals x squared + x.
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
it equals x1 it equals x1
16
X squared = x+6 6+x=x squared X=6
2
4
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
Well pythagorus theoreum is a squared plus b squared equals c squared and circumference equals pie x diameter and area equals pie x radius squared
They are +/- 5*sqrt(2)