2 x 6 = 12 2 x 2 x 3 = 12
x^2 + 24x = 0 add to both sides 12^2 (144) x^2 + 24x + 12^2 = 12^2 use the formula (a + b)^2 = a^2 + 2ab + b^2; (x + 12)^2 = 12^2 x + 12 = +, - 12 subtract 12 to both sides; x = 0 or x = -24
2 x 6 = 12 2 x 2 x 3 = 12
If the equation is structured like this: (8/x)=(12/(x+2)) then x=4. If the equation is structured like this: (8/x)=(12/x)+2 then x=-2.
(x^2 - x - 12) = (x^2 - 4x + 3x -12) = x(x -4) + 3(x -4) = (x-3) x (x-4) Hence (x^2 - x - 12) divided by (x -4) is (x-3)
You need to be careful in how you write such questions as it is important to know if you mean: x - 12/2 = 18 or (x-12)/2 = 18 If x - 12/2 = 18 then x = 18 + 12/2 x = 18 + 6 x = 24 If (x-12)/2 = 18 then x - 12 = 18 * 2 x - 12 = 36 x = 36 + 12 x = 48
The prime factors of 12 are 2 and 3. 2 x 2 x 3 = 12
2+x-4 = 12 x = 12+4-2 x = 14
2 x 2 x 3 is the prime factorization of 12. 12 can be found by multiplying 2 x 2 x 3.
2 x 2 x 3 = 12 2 x 2 x 2 x 3 = 24
12 = 2 x 2 x 3 16 = 2 x 2 x 2 x 2
2 x 2 x 2 x 2 = 16 2 x 2 x 3 = 12
-6 X -2 (-1)6X(-1)2 (-1)(-1)12 12
2 divided by x-12-x divided by x-2 is -1/(6(x-2)).
2 x 2 x 3 = 12 2 x 2 x 2 x 2 x 3 = 48
2x - 12 > 2 + x x - 12 > 2 x > 14
2 x 2 x 2 = 8 2 x 2 x 3 = 12