x = 7 and 2/3
7x5=3x-9 35=3x-9 35+9=3x 44=3x 44/3=x 14.3=x x=14.3
f(x1) = (-5)2 + 3*(-5) + 5.1 = 25 - 15 + 5.1 = 15.1 f(x2) = (6)2 + 3*(6) + 5.1 = 36 + 18 + 5.1 = 59.1 f(x2)-f(x1) = 59.1 - 15.1 = 44 x2 - x1 = 6 - (-5) = 11 So average rate of change = 44/11 = 4
Let the unknown number be called x: 3x-11 = x+33 3x-x = 33+11 2x = 44 x = 22 So the number is 22
11 times 4 1times 44
m-38=-44 [add 38 to both sides m=-6 The answer is 6 [six]
3x-5+2x=-49 is the same as 5x=-44 or x=-44/5
(3,7)
y = 3x 5x + 2y = 44 substitute 3x for y into the second equation 5x + 2(3x) = 44 5x + 6x = 44 11x = 44 divide by 11 to both sides x = 4 y = 3x substitute 4 for x y = 3(4) = 12 So the solution for the system is the intersection point (4, 12).
Let the numbers be x and y:- If: x+3y = -4 and 3x+y = 44 Then: 3x+9y = -12 and 3x+y = 44 Subtracting 3x+9y = -12 from 3x+y = 44: -8y = 56 => y = -7 By substitution: x = 17 and y = -7 Check: 17+3(-7) = -4 Check: 3(17) -7 = 44 Therefore the two numbers are: 17 and -7
Through a process of elimination and substitution the solutions are s = 8 and x = 5
7x5=3x-9 35=3x-9 35+9=3x 44=3x 44/3=x 14.3=x x=14.3
44.
44 + 3676 + 601 = 4321
x = 13 x 12 + 1 = 43 x 1 + 1 = 43 + 1 = 44 = 4
The addition problem 221 plus 44 plus 6 equals to 271.
There are many combinations of numbers that can equal 44 when added together. For example, 20 plus 24 equals 44, and 30 plus 14 also equals 44. You can also use other pairs, like 10 plus 34 or 5 plus 39. Essentially, any two numbers that sum to 44 will work.
44 + 4 = 48.