7x5=3x-9 35=3x-9 35+9=3x 44=3x 44/3=x 14.3=x x=14.3
f(x1) = (-5)2 + 3*(-5) + 5.1 = 25 - 15 + 5.1 = 15.1 f(x2) = (6)2 + 3*(6) + 5.1 = 36 + 18 + 5.1 = 59.1 f(x2)-f(x1) = 59.1 - 15.1 = 44 x2 - x1 = 6 - (-5) = 11 So average rate of change = 44/11 = 4
Let the unknown number be called x: 3x-11 = x+33 3x-x = 33+11 2x = 44 x = 22 So the number is 22
11 times 4 1times 44
m-38=-44 [add 38 to both sides m=-6 The answer is 6 [six]
3x-5+2x=-49 is the same as 5x=-44 or x=-44/5
(3,7)
y = 3x 5x + 2y = 44 substitute 3x for y into the second equation 5x + 2(3x) = 44 5x + 6x = 44 11x = 44 divide by 11 to both sides x = 4 y = 3x substitute 4 for x y = 3(4) = 12 So the solution for the system is the intersection point (4, 12).
Let the numbers be x and y:- If: x+3y = -4 and 3x+y = 44 Then: 3x+9y = -12 and 3x+y = 44 Subtracting 3x+9y = -12 from 3x+y = 44: -8y = 56 => y = -7 By substitution: x = 17 and y = -7 Check: 17+3(-7) = -4 Check: 3(17) -7 = 44 Therefore the two numbers are: 17 and -7
Through a process of elimination and substitution the solutions are s = 8 and x = 5
7x5=3x-9 35=3x-9 35+9=3x 44=3x 44/3=x 14.3=x x=14.3
44.
40+48=88. 81 + 7 = 88...
x = 13 x 12 + 1 = 43 x 1 + 1 = 43 + 1 = 44 = 4
44 + 3676 + 601 = 4321
The addition problem 221 plus 44 plus 6 equals to 271.
44 + 4 = 48.