D = {x [element of reals]}R = {y [element of reals]|y >= 4}
Only when X or Y = 0 That is because (x + y) squared = x^2 + 2xy + y^2 x^2 + 2xy + y^2 = x^2 + y^2 when x or y = 0
X + y
You must use the difference of squares formula: x2 - y2 = (x + y)(x - y) Thus: x2 - 25 = (x + 5)(x - 5).
The GCF is xy
x cubed y cubed z squared
2
(x2y2)3 + (x3y3)2 = 2x6y6.
it is (x-y)(x-y) :)
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
if you take your time youll figure out its e=mc2
You have to put your heart into it!
x^2 - y^2 - 4 is in its simplest form.
There are no rational factors.
(x, y) = (-3, -3) or (3, 3)
(x - y)(x + y)
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.