x^2 - y^2 - 4 is in its simplest form.
(4x - 7y)(4x + 7y)
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12. y = 1.128666978776461 y = -0.2953336454431275
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
3 * x * x * y
it is (x-y)(x-y) :)
There are no rational factors.
x^2 - y^2 - 4 is in its simplest form.
(x - y)(x + y)
2
y² - y - 6 = (y + 2)(y - 3)
You have to put your heart into it!
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
(y - 2)(y - 7)
4(y - 3)(y + 3)
( x - y )2There isn't enough information to answer this question because they have two squared variables and you do not know what is being squared. You would first need to either know the value of one of the variables and an equation of the value of both of the variables before you would be able to factor.