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What else can I help you with?
How do you factor x squared minus y squared minus four?
x^2 - y^2 - 4 is in its simplest form.
What is the factor ofsixteen x squared-fortynine y squared?
(4x - 7y)(4x + 7y)
How do you factor 6y squared - 5y - 2?
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12. y = 1.128666978776461 y = -0.2953336454431275
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
When you completely factor 3x2 y what do you get?
3 * x * x * y
How do you factor x squared minus 2 x y plus y squared?
it is (x-y)(x-y) :)
How do you factor x squared minus four y squared minus twenty eight?
There are no rational factors.
How do you factor x squared minus y squared minus four?
x^2 - y^2 - 4 is in its simplest form.
How do you factor completely x square minus y squared?
(x - y)(x + y)
If x squared minus y squared equals 10 and x plus y equals 5 what is x minus y?
2
How do you factor Y squared minus y minus 6?
y² - y - 6 = (y + 2)(y - 3)
X squared plus y squared minus 1 all cubed then minus the product of x squared times y cubed that all equals 0 How do you solve for y?
You have to put your heart into it!
How do you factor out completely x squared y minus y cubed?
To factor out the expression: x2y-y3 First factor out one "y": y(x2-y2) The expression x2-y2 is a difference of squares, which factors as well: (y)(x-y)(x+y) This is the simplest factoring of the original expression.
What is the factor of the quantity x plus y squared?
X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)
How do you factor y squared minus 9y plus 14?
(y - 2)(y - 7)
How do you factor 4y squared minus 36?
4(y - 3)(y + 3)
Factor x squared minus y squared?
( x - y )2There isn't enough information to answer this question because they have two squared variables and you do not know what is being squared. You would first need to either know the value of one of the variables and an equation of the value of both of the variables before you would be able to factor.
