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Q: How do you factor x squared minus y squared?

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x^2 - y^2 - 4 is in its simplest form.

(4x - 7y)(4x + 7y)

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (5 plus or minus the square root of 73) divided by 12. y = 1.128666978776461 y = -0.2953336454431275

x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)

3 * x * x * y

Related questions

it is (x-y)(x-y) :)

There are no rational factors.

x^2 - y^2 - 4 is in its simplest form.

(x - y)(x + y)

x2 - y2 = 16 then (x + y)*(x - y) = 16 This has an infinite number of solutions lying on the hyperbola.

2

y² - y - 6 = (y + 2)(y - 3)

There is a formula for the "difference of squares." In this case, the answer is (8x + 5y)(8x - 5y)

You have to put your heart into it!

xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1

X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)

2y(y + 3)(y - 7)

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