x + 7 + y
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x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)
x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
x-intercept happens when y=0 0=x2+6x-7 0=(x - 1)(x + 7) x-intercepts are x=1 and -7