yes.
x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)
x - y = 5 + 2x + y = 7 => 3x + 0 = 12 => 3x = 12 => 3x/3 = 12/3 => x=4 x-y=5 2x+y=7 =>4-y=5 =>2(4)+y=7 =>y=4-5 =>8+y=7 =>y=-1 =>y=-1 So, the answer would be x=4 and y=-1
x-intercept happens when y=0 0=x2+6x-7 0=(x - 1)(x + 7) x-intercepts are x=1 and -7
y=7+x =x=7-x
Y = x - 7
y=(7-x)/4
Another solution for x+y = 7 is y = -x+7
y = x + 7
If you mean: y^2 + x^2 = 65 and y + x = 7 then the solutions are as follows:- When y = -1 then x = 8 When y = 8 then x = -1
There could be many answers. If X=(-14) then Y=7 If X=0 then Y= (-7) etc.
The intercept is [ y = 7 ] .
x + 7y = 7 ⇒ 7y = -x + 7 ⇒ y = -x/7 + 1 ⇒ y intercept is 1.
If: x = 7 Then: y = (2*7)+3 = 17 And: 5x+y = (5*7)+17 = 52
(x - y + 7)(x + y)
The given expression is the same as 15+x+y simplified