Q: Y2 plus x2 65 y plus x 7?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

7

7

(x - y + 7)(x + y)

Center is (0, 0) . . . the origin.Radius is 7.

There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1

Related questions

7

7

(x - y + 7)(x + y)

x2 + 3y = 7 3x + y2 = 3 3y = x2 + 7 y2 = -3x + 3 y = x2/3 + 7/3 y = ± √(-3x + 3) If you draw the graphs of y = x2/3 + 7/3 and y = ± √(-3x + 3) in a graphing calculator, you will see that they don't intersect, so that the system of the given equations has not a solution.

Center is (0, 0) . . . the origin.Radius is 7.

There appear to be 10 terms in the determinant. A determinant can only have a perfect number of terms. So something has gone wrong with the question. 1: x2 plus 1 2: xy 3: xz 4: xy 5: y2 plus 1 6: yz 7: 1 plus x2 plus y2 plus z2 8: xz 9: yz 10: z2 plus 1

The center of the circle is at (9, 7) on the Cartesian plane

x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.

let (x1, y1) = (4, 7) and ( x2, y2) = ( 7, -8). Then, Slope = m = (y2 - y1)/(x2 - x1) m = (-8 - 7)/(7 - 4) m = -15/3

Centre = (4, -3) Radius2 = (4 + 2)2 + (-3 + 7)2 = 36 + 16 = 52 Equation = (x - 4)2 + (y + 3)2 = 52 or x2 - 8x + y2 + 6x = 27

Do you mean the following? x2 = 4 - 7x If so, then: x2 + 7x = 4 x2 + 7x + 49/4 = 4 + 49/4 (x + 7/2)2 = 65/4 x + 7/2 = ±√65 / 2 x = (-7 ± √65) / 2 So x is equal to (-7 - √65) / 2 and (-7 + √65) / 2

x2+y2=7^2newtest3