Equate it to zero (0) , and you have a quadratic equation that can be factotred.
Hence
x^2 + 12x + 36 = 0
(x + 6)(x + 6) = 0
Hence x = -6
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
Remember that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circles centre Rearrange the equation: x2-12x+y2+10y = -12 Complete the squares: (x-6)2+(y+5)2 = 36+25-12 => 49 Therefore: centre = (6, -5) and radius = 7
find out what 6 squared equals. which is 6 x 6 and that equals 36
X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
This is not an inequality. This is an equation.12x+7=43 12x=36 x=3
x^2 + 12x = 5 x^2 + 12x + __ = 5 + __ x^2 + 12x + 36 = 5 + 36 (The 36 I got from taking half of 12 and then squaring that number (which is 6).) (x + 6)^2 = 41 x + 6 = (the square root of 41) x = (the square root of 41) - 6. Hope that helped :)
x=5/2*sqr(3)
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
Depending on whether or not there are implied brackets: x + 62 = x + 36 (x + 6)2 = x2 + 12x + 36
x2-12x+36 = (x-6)2
To calculate 6 squared plus 8 squared, you first need to square each number individually. 6 squared is 6 x 6, which equals 36. 8 squared is 8 x 8, which equals 64. Adding these two results together, you get 36 + 64, which equals 100. So, 6 squared plus 8 squared is 100.
x = plus or minus 6.
The graph is a circle with a radius of 6, centered at the origin.
x = ±2
62 = 36