0
Equate it to zero (0) , and you have a quadratic equation that can be factotred.
Hence
x^2 + 12x + 36 = 0
(x + 6)(x + 6) = 0
Hence x = -6
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X2 plus 12x plus 36 equals 0?
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
How do you find the the center of a circle and its radius when its equation is x squared plus y squared equals 12x -10y -12?
Remember that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circles centre Rearrange the equation: x2-12x+y2+10y = -12 Complete the squares: (x-6)2+(y+5)2 = 36+25-12 => 49 Therefore: centre = (6, -5) and radius = 7
What is evaluate six squared?
find out what 6 squared equals. which is 6 x 6 and that equals 36
What is A squared plus 6 squared equals 12 squared?
a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.
What number must you add to complete the square x2 plus 12x equals 16?
Add? I will show you the process. X^2 + 12X = 16 halve the linear term (12), square it and ADD it to both sides X^2 + 12X + 36 = 16 + 36 factor the right side; gather terms right (X + 6)^2 = 52 (X + 6)^2 - 52 = 0 (-6,-52) vertex of function As you see 36 was added to both sides
